Pei Hwa Presbyterian Primary
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JRLam:
Thank you.... looks challenging!!... will try them in a while...Here are the last 3 problem sums in this year's P5 MA P2 -
SCSS:
As an ex-PHPPS student, I was quite lay back when I was in sec school, didnt like to ask T questions cos preferred to self study.... only woke up around JC time but was challenging T with out of scoop questions instead...er.... , Just to answer your qn - my fren said the PHSS student are quite lay back (er... i think he means they are passive learner..) . No offence, pls.
Dont think your fren will like this type of student instead.... imho, if they are learning, passive or active also can lah.... :siam:
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S6169:
Alegbra was taught only in P6 term 1 (during my elder boy's P6) - a very small chapter, clearly incapable of solving the so-called challenging prob sums. Better to learn it from pte tutors.
May I know at which level can the algebra be used to slove the problem?JRLam:
Here are the last 3 problem sums in this year's P5 MA P2 -
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JRLam:
1.Here are the last 3 problem sums in this year's P5 MA P2 -
1. 975 boys and girls attended the school's sports day. After 5/7 of the boys and 3/4 of the girls left, there were 150 more boys than girls who remained. How many girls attended the sports day at first?
2. Annika saved a total of 228 pieces of 10-cent coins, 20-cent coins and 50-cent coins.
She added more coins to her collection until the number of 10-cent coins tripled, removed 1/2 of the number of 20-cent coins and took out 18 pieces of 50-cent coins.
The ratio of the number of 10-cent coins to 20-cent coins to 50-cent coins is now 3:6:2
Find the total value of all the coins Annika has now
3. A group of people attended a party. Each of them shook hands with everyone else once only. Mary shook with 5 times as many girls as boy. John shook hands with 6 times as many girls as boys.
a) How many people attended the party?
b) Were there more boys or girls? How many more?
Have fun!
B -> 1/7boy
G -> 1/4girl
a.\tBBBBBBB + GGGG -> 975
b.\tBB-G -> 150,
BB BB BB BB β GGGG -> 150X4 =600
a + b, \tBβ¦β¦B (15units) -> 975+600=1575
B -> 1575/15=105
β¦β¦
240 girls attended the sports day at first.
2.
1+6X2+2 (units) -> 228-18=210pieces
1unit ->14pieces
$0.10 -> 14X3X$0.10=$4.20
$0.20 -> 14X6X$0.20=$16.80
$0.50 -> 14X2X$0.50=$14.00
$4.20+$16.80+$14.00=$35.00
The total value of all the coins Annika has $35.00 now.
3.
the girls number should be 6multiples and 5multiples+1.
a) 43 people attended the party. there are 36 girls and 7 boys.
b) There were more girls. -
S6169:
Alegbra was taught only in P6 term 1 (during my elder boy's P6) - a very small chapter, clearly incapable of solving the so-called challenging prob sums. Better to learn it from pte tutors.[/quote]JRLam:
Here are the last 3 problem sums in this year's P5 MA P2 -
May I know at which level can the algebra be used to slove the problem?
Algebra very pathetic chapter at P6 (first chap)...took a glimpse of the textbook when I was at Popular...like what Jennifer mentioned, it's totally incapable of solving any problem. Son was taught Models to handle Maths problems.
Students in school are not equipped with sufficient methods of handling prob sums although they are given marks for diff steps (M1, M2 thing) :?
So, that's why private tutors are needed. -
janet_lee88:
Alegbra was taught only in P6 term 1 (during my elder boy's P6) - a very small chapter, clearly incapable of solving the so-called challenging prob sums. Better to learn it from pte tutors.[/quote]Algebra very pathetic chapter at P6 (first chap)...took a glimpse of the textbook when I was at Popular...like what Jennifer mentioned, it's totally incapable of solving any problem. Son was taught Models to handle Maths problems.S6169:
[quote=\"JRLam\"]Here are the last 3 problem sums in this year's P5 MA P2 -
May I know at which level can the algebra be used to slove the problem?
Students in school are not equipped with sufficient methods of handling prob sums although they are given marks for diff steps (M1, M2 thing) :?
So, that's why private tutors are needed.[/quote]
That means the Algebra can be used from P5 onwards as soon as the kids know how to use and give correct answer. -
lizhi:
To me, this is like a Algebra.
1.
B -> 1/7boy
G -> 1/4girl
a.\tBBBBBBB + GGGG -> 975
b.\tBB-G -> 150,
BB BB BB BB β GGGG -> 150X4 =600
a + b, \tBβ¦β¦B (15units) -> 975+600=1575
B -> 1575/15=105
β¦β¦
240 girls attended the sports day at first. -
IJJ:
Curious if you continue to keep till school reopens, any difference ? On second thoughts might be better, cos your child will surely hand in to Form T, better rightTrapwithin:
Submitted before school closed.
Better submit soon.
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markfch:
What was the mean score for P5 SA1 maths again? :nailbite:
For last year 2010 SA2 P5 MA Highest was 93, Avg was 58 and Median was 60, not easy :nailbite: -
Hi markfch,
Thanks for the information.
I will have no doubt on the hygiene level @ Student Care Junction since it is managed by the mummy volunteers.
Didn't know that the quota for accepting the children is so low. Only 20 out of hundreds of students?
In that case, must look for alternatives already.
thanks for the useful info.. -
markfch:
Ya, bad timing! Aiya, I was just fulfilling the promise I made to P3/4 parents after SA1 to put up the questions ...for all you know, most parents may find them 'wet-wet-water' lah, like LizhiJust when we were consoling ourselves not to be scared by PH's std and then you post this. :yikes:
What was the mean score for P5 SA1 maths again? :nailbite:
... they will heave a sign of relief instead :laugh:
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