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    Q&A - P3 Math

    Scheduled Pinned Locked Moved Primary 3
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      bookwormkids:
      P3 Maths


      A watch costs $100 more than a pen. The watch also costs twice as much as a ring. The total cost of the 3 items is $250. Find the cost of the pen.

      Thanks!
      Hi

      using MD ...

      http://i56.tinypic.com/2a0gaww.jpg\">

      cheers.

      1 Reply Last reply Reply Quote 0
      • B Offline
        bookwormkids
        last edited by

        Hi jedamum!

        Thanks for your solution. Your solution is perfectly acceptable so long as the kid understand it... 😄 I was stucked at the pen and the watch part. Thanks for your solution, now I know where goes wrong. 😄

        1 Reply Last reply Reply Quote 0
        • B Offline
          bookwormkids
          last edited by

          Hi MathIzzzFun!


          With your model, I think I could clear my kid's query! Thanks for your help! 😄

          1 Reply Last reply Reply Quote 0
          • A Offline
            aps
            last edited by

            Hi all


            Please help me with this question. I need the model approach. Thanks.

            John bought some books which cost an average of $26. Two of the books cost $46 and $34 respectively. If the average cost of the remaining books was $22, find the total number of books he bought.

            1 Reply Last reply Reply Quote 0
            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              aps:
              Hi all


              Please help me with this question. I need the model approach. Thanks.

              John bought some books which cost an average of $26. Two of the books cost $46 and $34 respectively. If the average cost of the remaining books was $22, find the total number of books he bought.
              Hi

              There is a similar question which was discussed at this thread - http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=27&t=6373&hilit=overall+average+will+be+85&start=3630

              cheers.

              1 Reply Last reply Reply Quote 0
              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                bookwormkids:
                Hi MathIzzzFun!


                With your model, I think I could clear my kid's query! Thanks for your help! 😄
                u r welcome.

                cheers.

                1 Reply Last reply Reply Quote 0
                • W Offline
                  whywhy
                  last edited by

                  Tin A contains some 20-cents coins and Tin B contains some 50-cents coins.

                  There are 9 more coins in Tin A than in Tin B.
                  The amount of money in Tin A is $2.70 less than that in Tin B.
                  How many 50-cents coins are there in Tin B ?

                  Is guess and check the only method to solve this Question???

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    whywhy:
                    Tin A contains some 20-cents coins and Tin B contains some 50-cents coins.

                    There are 9 more coins in Tin A than in Tin B.
                    The amount of money in Tin A is $2.70 less than that in Tin B.
                    How many 50-cents coins are there in Tin B ?

                    Is guess and check the only method to solve this Question???
                    Hi

                    Suppose or pretend that you remove 9 20 cents coins from Tin A.

                    9*20 ---- 180

                    Now Tin A has (270+180) or 450 cents less than Tin B

                    Difference in value between a 50 cents coin and 20 cents coin ------ 30 cents.

                    450/30 ------ 15

                    There are 15 50 cents coins in Tin B.

                    Best wishes

                    1 Reply Last reply Reply Quote 0
                    • P Offline
                      pixiedust
                      last edited by

                      Is this P4/P5 question ?


                      …num of coins…*…value…Total amt of money
                      Tin A…U+9…20cents…20U+180
                      Tin B…U…50cents…50U
                      (…for alignment purpose)

                      50U = 20U + 180 + 270 = 20U + 450
                      30U = 450
                      U=15

                      Ans: There are 15 50-cents coins in Tin B.

                      ---------------------------------------------------
                      check :
                      Tin B: 15 coins -> 15 x 50cents = $7.50
                      Tin A: 24 coins -> 24 x 20cents = $4.80
                      $7.50-$4.80=$2.70, checked

                      1 Reply Last reply Reply Quote 0
                      • P Offline
                        pixiedust
                        last edited by

                        tianzh’s method is faster and more elegant !

                        1 Reply Last reply Reply Quote 0

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