Tutor MathsGuru: Ask me for your burning Maths questions!

[MathIzzzFun]

Herbie:

I hv one qn.

The cost of a movie icket for an adulr is x, while $4 less. On a particular day, the ratio of the no. Of adults to children watching a movie was 1:6, they spent $322 in total.
Express the no. Of adults watching the movie in terms of x.

Tq

Hi

some parts of the question is missing..I will presume the cost of child ticket is $4 less.

1 Adult --> $ x
1 child --> $(x-4), 6 child --> $ 6(x-4)

1 adult + 6 children --> $x + $ 6x - $24 = $ (7x - 24)

Number of adults = 322/(7x-24)

cheers.

[Kafer]

hi mathsizzfun please help


In a confectionary, 3/10 of the cupcakes baked were strawberry cupcakes, 1/2 of them were chocolate cupcakes and the rest were grape cupcakes.
2/7 of the strawberry cupcakes were sold. This was 1/2 of the chocolate cupcakes sold. The no. of grapes cupcakes sold was 1/4 the total no. sold in the other two flavours. Given that there were 190 cupcakes left, how many cupcakes were there at first?

[MathIzzzFun]

Kafer:

hi mathsizzfun please help


In a confectionary, 3/10 of the cupcakes baked were strawberry cupcakes, 1/2 of them were chocolate cupcakes and the rest were grape cupcakes.
2/7 of the strawberry cupcakes were sold. This was 1/2 of the chocolate cupcakes sold. The no. of grapes cupcakes sold was 1/4 the total no. sold in the other two flavours. Given that there were 190 cupcakes left, how many cupcakes were there at first?

Hi

at first,
S : C : G = 3 : 5 : 2 --> 42u : 70u : 28 u (total 140u)
2/7 of S sold --> 12u
So, number of C sold --> 24u
G sold --> 1/4 x 36u = 9u
Total sold --> 45u
Left --> 140u - 45u = 95u
95u --> 190, 1u --> 2

Total number of cupcakes, at first --> 2 x 140 = 280

cheers.

[Always21]

Hi Maths Guru,


Can help me with this problem?

Ray and Jim had an equal amount of money. Ray spent $85 on the watch and Jim spent $189 on a camera. As a result, Ray had thrice as much as money as Jim had left. How much money did each of them have at first?

[MathIzzzFun]

Always21:

Hi Maths Guru,


Can help me with this problem?

Ray and Jim had an equal amount of money. Ray spent $85 on the watch and Jim spent $189 on a camera. As a result, Ray had thrice as much as money as Jim had left. How much money did each of them have at first?

Hi

In the end,
Jim --> 1 unit
Ray --> 3 units

At first,
Jim --> 1 unit + $189
Ray --> 3 units + $85
So, 1 unit + $189 = 3 units + $85
2 units --> $ 104
1 unit --> $52

1 unit + $ 189 --> $241

Each has $241 at first.

cheers.

[Always21]

Many thanks

[Bunny27]

Always21:

Many thanks

Hi, someone pls help on this question. TIA

1. Cheryl, Siti and Audrey have some money.
If Cheryl gives $3.50 to Siti, the two girls will have an equal amount of money. If Siti gives $3.50 to Cheryl, Cheryl will have 3 times as much money as Siti. Audrey's share is the sum of the other girls.
How much money do they have altogether?

[MathIzzzFun]

Bunny27:

Always21:

Many thanks

Hi, someone pls help on this question. TIA

1. Cheryl, Siti and Audrey have some money.
If Cheryl gives $3.50 to Siti, the two girls will have an equal amount of money. If Siti gives $3.50 to Cheryl, Cheryl will have 3 times as much money as Siti. Audrey's share is the sum of the other girls.
How much money do they have altogether?

Hi

Try drawing a model and you should be able to visualize the transfers..alternatively you could also use ratios/units & parts approach to solve this ...


If Cheryl gives $3.50 to Siti, the two girls will have an equal amount of money --> So, Cheryl has $ 7.00 more than Siti

If Siti gives $3.50 to Cheryl, Cheryl will have 3 times as much money as Siti --> Cheryl has $7.00 more than Siti, if Siti gives $3.50 to Cheryl, Cheryl would have $7.00 + $7.00 = $ 14.00 more than Siti. We have
Cheryl --> 3 units
Siti --> 1 unit and therefore 2 unit --> $ 14.00, 1 unit --> $ 7.00

Total amount of money --> Audrey's money + Cheryl's money + Siti's money = 4 units + 3 units + 1 unit --> 8 x $ 7.00 = $ 56.00 (Cheryl $ 17.50, Siti $10.50, Audrey $28.00)


cheers.

[violin_lover]

Good reasoning

[kwcllf]

Hi please help with the following question:


Classes 6A and 6B have the same number of pupils. The ratio of the number of boys in 6A to 6B is 4:3. The ratio of the number of girls in 6A to the number of girls in 6B is 4:7. Find the ratio of the number of boys to the number of girls in 6A.

Thanks