Tutor MathsGuru: Ask me for your burning Maths questions!

[MathIzzzFun]

esibuyer:

Hi, can solve the following question for my girl.

Grandma is 80 years old and his son is 52 years old. How many years ago was Grandma thrice as old as his son?
Thanks

Hi

Age difference will always remain the same.

Age difference = 80 - 52 = 28
When grandma was 3 times as old as her son,
grandma's age --> 3u
son's age --> 1u
age difference --> 2u
2u --> 28, 1u --> 14
52-14 = 38 years ago

cheers.

[ongmt]

1) Dan harvested some apples. He sold to Adam 3/4 of the apples and another 105 apples. He sold to Geradine 3/4 of the remainder but took back 55 apples. Dan had 890 apples left.


a) How many apples did Geradine have after returning 55 apples to Dan
b) How many apples did Farmer Dan harvest?

2) Tank X and Y are each filled with some water. If water from tank Y is poured into Tank X until water in tank X reaches the brim, there will be 8L of water left in Tank Y, If water from Tank X is poured into Tank Y until water in Tank Y reach the brim, there will be 26L of water leftt in Tank X. The ratio of volume of of Tank X to Taank Y is 5 : 3. How many more litres of water are needed to fill both tanks to their brim?

3)A florist had total 272 roses and lilies in ratio of 12:5. After selling away twice as many roses as Lilies, the ratio of roses to Lilies was 5:2. How many roses did she shell?

Plse help. Thks

:slapshead:

[MathIzzzFun]

ongmt:

1) Dan harvested some apples. He sold to Adam 3/4 of the apples and another 105 apples. He sold to Geradine 3/4 of the remainder but took back 55 apples. Dan had 890 apples left.


a) How many apples did Geradine have after returning 55 apples to Dan
b) How many apples did Farmer Dan harvest?

2) Tank X and Y are each filled with some water. If water from tank Y is poured into Tank X until water in tank X reaches the brim, there will be 8L of water left in Tank Y, If water from Tank X is poured into Tank Y until water in Tank Y reach the brim, there will be 26L of water leftt in Tank X. The ratio of volume of of Tank X to Taank Y is 5 : 3. How many more litres of water are needed to fill both tanks to their brim?

3)A florist had total 272 roses and lilies in ratio of 12:5. After selling away twice as many roses as Lilies, the ratio of roses to Lilies was 5:2. How many roses did she shell?

Plse help. Thks

:slapshead:

Hi

Q1. You should be able to solve this... I will provide some pointers...
Before Geraldine returned the apples to Dan, how many did Dan have ? This number represent 1/4 of the remainder after selling Geraldine the apples. You can work backwards from here.

Q2.
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Q3.
At first,
Roses --> 12/17 x 272 = 192
Lilies --> 272 - 192 = 80

Roses left : Lilies left
= 192-2u : 80 - 1u
= 5 : 2

cross multiply or equalize:
384 - 4u = 400 - 5u
1u = 16

Roses sold --> 2 x 16 = 32

cheers.

[Herbie]

I hv one qn.

The cost of a movie icket for an adulr is x, while $4 less. On a particular day, the ratio of the no. Of adults to children watching a movie was 1:6, they spent $322 in total.
Express the no. Of adults watching the movie in terms of x.

Tq

[MathIzzzFun]

Herbie:

I hv one qn.

The cost of a movie icket for an adulr is x, while $4 less. On a particular day, the ratio of the no. Of adults to children watching a movie was 1:6, they spent $322 in total.
Express the no. Of adults watching the movie in terms of x.

Tq

Hi

some parts of the question is missing..I will presume the cost of child ticket is $4 less.

1 Adult --> $ x
1 child --> $(x-4), 6 child --> $ 6(x-4)

1 adult + 6 children --> $x + $ 6x - $24 = $ (7x - 24)

Number of adults = 322/(7x-24)

cheers.

[Kafer]

hi mathsizzfun please help


In a confectionary, 3/10 of the cupcakes baked were strawberry cupcakes, 1/2 of them were chocolate cupcakes and the rest were grape cupcakes.
2/7 of the strawberry cupcakes were sold. This was 1/2 of the chocolate cupcakes sold. The no. of grapes cupcakes sold was 1/4 the total no. sold in the other two flavours. Given that there were 190 cupcakes left, how many cupcakes were there at first?

[MathIzzzFun]

Kafer:

hi mathsizzfun please help


In a confectionary, 3/10 of the cupcakes baked were strawberry cupcakes, 1/2 of them were chocolate cupcakes and the rest were grape cupcakes.
2/7 of the strawberry cupcakes were sold. This was 1/2 of the chocolate cupcakes sold. The no. of grapes cupcakes sold was 1/4 the total no. sold in the other two flavours. Given that there were 190 cupcakes left, how many cupcakes were there at first?

Hi

at first,
S : C : G = 3 : 5 : 2 --> 42u : 70u : 28 u (total 140u)
2/7 of S sold --> 12u
So, number of C sold --> 24u
G sold --> 1/4 x 36u = 9u
Total sold --> 45u
Left --> 140u - 45u = 95u
95u --> 190, 1u --> 2

Total number of cupcakes, at first --> 2 x 140 = 280

cheers.

[Always21]

Hi Maths Guru,


Can help me with this problem?

Ray and Jim had an equal amount of money. Ray spent $85 on the watch and Jim spent $189 on a camera. As a result, Ray had thrice as much as money as Jim had left. How much money did each of them have at first?

[MathIzzzFun]

Always21:

Hi Maths Guru,


Can help me with this problem?

Ray and Jim had an equal amount of money. Ray spent $85 on the watch and Jim spent $189 on a camera. As a result, Ray had thrice as much as money as Jim had left. How much money did each of them have at first?

Hi

In the end,
Jim --> 1 unit
Ray --> 3 units

At first,
Jim --> 1 unit + $189
Ray --> 3 units + $85
So, 1 unit + $189 = 3 units + $85
2 units --> $ 104
1 unit --> $52

1 unit + $ 189 --> $241

Each has $241 at first.

cheers.

[Always21]

Many thanks