Q&A - P5 Math
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Mrs Wong bought 6kg of beef and 2kg of mutton. mrs lim bought 6kg of mutton and 2kg of beef. mrs wong paid $20 more than mrs lim. if 1 kg of mutton cost $8 find the cost of 1kg of beef
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carol73:
Mrs Wong bought 6kg of beef and 2kg of mutton. mrs lim bought 6kg of mutton and 2kg of beef. mrs wong paid $20 more than mrs lim. if 1 kg of mutton cost $8 find the cost of 1kg of beef
2kg mutton.....$16
6kg mutton......$48
48-16=32
32+20=52
52/4=$13 :imcool: -
redruby:
Tan was given a sum of money. He spent $460 on Monday and 1/3 of the remainder on Tuesday. On Wednesday, he spent another $300. Then Tan realized that he had 0.2 of the original sum of money left. Find the sum of money Tan was given?
Tan's money --> 10 units, 0.2 of Tan's money = 2 units
remainder after spending $460 --> 3 parts
2 parts = 2 units + $300
remainder --> 3 parts = 3 units + $450
Total = remainder + $460
10 units = 3 units +$450 + $460
7 units --> $910
10 units --> $1300
Tan was given $1300
cheers. -
1) Lydia spent $1735 on a television set. She spent 1/4 of the remaining money on a camera and still had 1/3 of her money left. How much money did Lydia spend altogether?
2) Dylan and Richard went shopping with $340 and $545 respectively. Dylan spent twice as much money as Richard. After shopping, the amount of money Richard had left was twice the amount of money Dylan had left. How much money did Dylan spend? -
KOOLMUM:
1)1) Lydia spent $1735 on a television set. She spent 1/4 of the remaining money on a camera and still had 1/3 of her money left. How much money did Lydia spend altogether?
2) Dylan and Richard went shopping with $340 and $545 respectively. Dylan spent twice as much money as Richard. After shopping, the amount of money Richard had left was twice the amount of money Dylan had left. How much money did Dylan spend?
<-------TV----------><1u Camera><3u Left>
<--------------6u--------------------><--3u--->
5u -> $1735
1u -> $347
Total amount spent -> $1735 + $347 = $2082 -
KOOLMUM:
2)1) Lydia spent $1735 on a television set. She spent 1/4 of the remaining money on a camera and still had 1/3 of her money left. How much money did Lydia spend altogether?
2) Dylan and Richard went shopping with $340 and $545 respectively. Dylan spent twice as much money as Richard. After shopping, the amount of money Richard had left was twice the amount of money Dylan had left. How much money did Dylan spend?
Dylan -> 340 - 2u -> 1p
Richard -> 545 - 1u -> 2p
680 - 4u = 545 - 1u
3u -> 680 - 545 = 135
1u -> 45
Dylan spent 2u (2 x 45) = $90 -
3) Danny’s key chains was 5/6 of Pamela’s key chains at first. Pamela gave 3/10 of her key chains to Danny. Danny then gave 1/4 of his key chains to Pamela. In the end, Danny had 32 fewer key chains than Pamela. How many key chains did Pamela have at first?
4) Lina bought a box of jigsaw puzzle. She fitted 2/7 of the pieces of the puzzle on the first day. On the second day, she fitted another 120 pieces of the puzzle. As a result, the number of the fitted pieces was 10/11 of the number of the unfitted pieces. How many pieces did the jigsaw puzzle consist of? -
Thank u so much, u r amazing.
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KOOLMUM:
At first,3) Danny's key chains was 5/6 of Pamela's key chains at first. Pamela gave 3/10 of her key chains to Danny. Danny then gave 1/4 of his key chains to Pamela. In the end, Danny had 32 fewer key chains than Pamela. How many key chains did Pamela have at first?
Danny's key chains --> 50 units
Pamela's key chains --> 60 units
Pamela gave 3/10 x 60 units = 18 units to Danny
Danny's key chains --> 50 units + 18 units = 68 units
Pamela's key chains --> 60 units - 18 units = 42 units
Danny gave 1/4 x 68 units = 17 units to Pamela
Danny's key chains --> 68 units - 17 units = 51 units
Pamela's key chains --> 42 units + 17 units = 59 units
Pamela had 32 key chains more than Danny
8 units --> 32, 1 unit --> 4
At first, Pamela's key chains --> 60 x 4 = 240
cheers. -
KOOLMUM:
similar question here --> http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=68&t=25129&start=2480
4) Lina bought a box of jigsaw puzzle. She fitted 2/7 of the pieces of the puzzle on the first day. On the second day, she fitted another 120 pieces of the puzzle. As a result, the number of the fitted pieces was 10/11 of the number of the unfitted pieces. How many pieces did the jigsaw puzzle consist of?
\"what remains the same\" --> the total number of pieces remain the same.
at first, fitted : unfitted --> 2 : 5 --> 6u : 15u -- total 21u
in the end, fitted : unfitted --> 10u : 11u -- total 21u
on 2nd day, 10u - 6u = 4u of puzzle pieces were fitted
4u --> 120, 1u --> 30
total number of pieces --> 21 x 30 = 630
cheers.
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