Q&A - P3 Math

[small]

MD..


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[pertunia]

Hi, anyone can help to solve this question? This is from my son’s assignment. The question is:


Hassan has some pokemon cards to share among his friends. If he gives each friend 6 pokemon cards, he will have 5 cards left. If he gives each friend 8 pokemon cards, he will be short of 7 pokemon cards. How many pokemon cards does Hassan have?


My son is taught to use the guess and check method for questions similar to this. However, the space given for this question is too little. It is like the space for a short question. Can anyone solve this in a very easy manner without using algebra?


Thanks so much.

[small]

Hassan has some pokemon cards to share among his friends. If he gives each friend 6 pokemon cards, he will have 5 cards left. If he gives each friend 8 pokemon cards, he will be short of 7 pokemon cards. How many pokemon cards does Hassan have? \t\t\t\t\t


Gap : 5+7 = 12

Different = 8 - 6 = 2\t\t\t\t\t\t\t\t
12 / 2 = 6 friends\t\t\t\t\t
\t\t\t
From red font :
6 cards x 6 + 5 cards
= 41 cards\t\t\t\t\t\t

Hassan have 41 pokemon cards altogether.

[small]

pertunia:

Hi, anyone can help to solve this question? This is from my son's assignment. The question is:


Hassan has some pokemon cards to share among his friends. If he gives each friend 6 pokemon cards, he will have 5 cards left. If he gives each friend 8 pokemon cards, he will be short of 7 pokemon cards. How many pokemon cards does Hassan have?


My son is taught to use the guess and check method for questions similar to this. However, the space given for this question is too little. It is like the space for a short question. Can anyone solve this in a very easy manner without using algebra?


Thanks so much.

Hi pertunia,

HTH..

Multiple of 6 + 5 : 29, 35, 41, 47, 53
Multiple of 8 - 7 : 25, 33, 41, 49, 57\t

Hassan have 41 pokemon cards altogether.

[Muffins]

Hi small,


just wondering, if multiples of numbers are their numbers that have been multiplied to give the result, wouldn’t the multiples of 11 (6+5) be 11, 22, 33 etc.

sorry for the inconvenience, but couldya pls explain? cannot understand…

[usaik]

Hi,


I need help with the following question. Many thanks in advance!

Jim had 2346 coins. He gave away 27 coins and his friend gave him 628 new coins. He then put the coins equally into 4 boxes.
(a) what was the greatest possible number of coins in each box?
(b) how many coins were left over?

[Muffins]

2346 - 27 = 2319


2319 + 628 = 2947

Rounding down 2947 to the nearest multiple of 4, we get 2944

So, the answer for a) is 2944

b) 2947 - 2944 = 3

Hope this helped!

[small]

Muffins:

Hi small,


just wondering, if multiples of numbers are their numbers that have been multiplied to give the result, wouldn't the multiples of 11 (6+5) be 11, 22, 33 etc.

sorry for the inconvenience, but couldya pls explain? cannot understand....

Hi Muffins,

From the question: If he gives each friend 6 pokemon cards, he will have 5 cards left.

It means the number will be multiple of 6 cards + 5 cards.

n=1; 6 x 1 + 5 = 11
n=2; 6 x 2 + 5 = 17
n=3; 6 x 3 + 5 = 23


Hope this helps..

[small]

Muffins:

2346 - 27 = 2319


2319 + 628 = 2947

Rounding down 2947 to the nearest multiple of 4, we get 2944

So, the answer for a) is 2944

b) 2947 - 2944 = 3

Hope this helped!

I think Muffins forgot to divide the total coins by 4:

2346 - 27 + 628 = 2947

2947 / 4 = 736 R3

a) 736 coins
b) 3 coins

.

[usaik]

small:

Muffins:

2346 - 27 = 2319


2319 + 628 = 2947

Rounding down 2947 to the nearest multiple of 4, we get 2944

So, the answer for a) is 2944

b) 2947 - 2944 = 3

Hope this helped!

I think Muffins forgot to divide the total coins by 4:

2346 - 27 + 628 = 2947

2947 / 4 = 736 R3

a) 736 coins
b) 3 coins

.

Hi Muffin, Hi Small,
Thanks for the enlightenment.
I initially thought I have to use esimate to solve this and was stuck for a long while. THANKS so much!!!