Q&A - P3 Math

[Herbie]

Can someone explain the "as much as" ?


Tx

[Muffins]

Daddy:

Hi Dharma,


I had came across this question. But the two conditions are different. Ones is short & the other is left. Add two together..

e.g: Sally bought 7 rings, she was short of $192. When she bought 5 rings, she had $88 left.

I just added the two value: $192+$88 = $280, then $280/2 = $140.

But came to this question: Both conditions are same. ???
\"When Sean bought 8 pens, he was short of $38. When he bought 10 pens, he was short of $110. How much money did he have?

How about if two conditions are left(remainder) of money. subract the 2 remainder.???

Any easy method to understand?...

Thanks alot...

Daddy

Hi Daddy!

You are absolutely right for 2 shorts and 1 left and 1 short, but for 2 lefts, you have to minus the lefts and do your equation, so, absolutely right, Daddy! :rahrah:

[Dharma]

Herbie:

Can someone explain the \"as much as\" ?


Tx

Hi Herbie,

“As much as” refers to comparison between 2 items.

For example, jug A contains 3 times as much water as Jug B. If Jug A contains 9 litres, then Jug B will have 3 litres.

[shurley197323]

Pls help.

(1) Jane’s age now is a 2-digit multiple of 4.Next year, her age will be multiple of 5. How old is Jane now ?

(2)Michelle has more thab 50 hairpins. If she puts them in pkts of 7, she has 5 hairpins left.If she puts them in pkts of 9, she has 6 hairpins left. How many hairpins does Michelle has?

Thanks

[corneyAmber]

shurley197323:

Pls help.

(1) Jane's age now is a 2-digit multiple of 4.Next year, her age will be multiple of 5. How old is Jane now ?

(2)Michelle has more thab 50 hairpins. If she puts them in pkts of 7, she has 5 hairpins left.If she puts them in pkts of 9, she has 6 hairpins left. How many hairpins does Michelle has?

Thanks

Both questions can use table to guess and check.

(1) I can see the answer is 24 because I know my times tables well. So to explain to the child, use a table

12-->13
16-->17
20-->18
24-->25

Jane is 24 years old now.

(2) 7 * u + 5 = 9 * v + 6
7 * u = 9 * v + 1

49 <-> 45+1 = 46
56 <-> 54+1 = 55
63 <-> 63 + 1 = 64
70 <-> 72 +1 =73
77 <-> 81 + 1 = 82
84 <-> 81+ 1 = 82
91 = 90+1 = 91

Michelle has 91 hairpins

[shurley197323]

Thanks. Ks2me. But still unclear about Q2. If u don’t mind, can explain in other ways?

[corneyAmber]

shurley197323:

Thanks. Ks2me. But still unclear about Q2. If u don't mind, can explain in other ways?

q1 n 2 are similar in concept. Both testing multiplication table.

In q1 it is told, the difference is 1 more straight forward to simulate the answer. In q2, I use the equation 7*u packets +5 =9*v packets + 6 = total number of hairpins to find out what is the difference amt like in q1.
Rearranging the equation, I get 7*u = 9*v +1. So now it becomes same as q1 pattern, can u see that?

In q2 harder to see directly becos it takes 7*13 to get 91 and usually our mental times table stops at 7*12 but right hand side easy to see 90+1 mentally. Anyway for p3/p4 level for guess n check method usually the multiples won't be too difficult.

Hope this explains better.
Basically math is alot about putting it into a pattern easy to see intuitively.

[Suz855]

Need help to validate answer, thanks



http://www.postimage.org/

[small]

Suz855:

Need help to validate answer, thanks



http://www.postimage.org/

Hi Suz855,

Hope this helps. My method might not so clear as I am still under learning stage. :oops:

http://s3.postimage.org/rd5ES-fe3f4cfd2c241f4acdbf433ec3730af2.png\">

[corneyAmber]

Small, I cannot see your answer image as it is not coming out on the screen.


Here's my solution:

1+2005 = 2006
3 +2003 = 2006
5 + 2001 = 2006
:
:
1 to 2005 = 2005 numbers
Number of odd numbers = 1003
So number of pairs of odd numbers to give total 2006 = 1002/2 = 501
so there are 501 whole numbers because (1+2005)/2006 = 1 + (3+2003)/2006=1 + ......................+ (1001+1005)/2006=1

Middle odd number without a pair would be = 1003

So 501 + 1003/2006 = 501 + 0.5 = 501.5

Is this P3/P4 question?