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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      imacsg:
      Hi,

      Can you help to solve the below question

      find x : 10, 16, 26, 40, 58, x

      Thanks
      Hi

      x = 80

      One way to solve number pattern is to find the difference of two consecutive terms... and repeat for pattern of \"difference\" until the difference is a constant.

      For this case, you can work out the 1st level difference pattern : 6,10,14,18
      and then down one more level and get the 2nd level difference pattern :
      4,4,4
      So, the 5th number in the 1st level difference pattern is 18+4 = 22
      and x = 58 + 22 = 80

      cheers.

      1 Reply Last reply Reply Quote 0
      • I Offline
        imacsg
        last edited by

        Hi

        Thanks.

        I nearly fainted when I see, the teacher asked them to use

        this equation an2 + bn + c to solve above question:

        Using Fx 95Sg Plus calculator, set Mode 3 (Equation Mode), Then choose 1.
        The calculator will have 3 columns (a), (b) and (c). Arrange your 2 equations like this:

        (a) (b) (c)
        b + c = 8
        2b + c = 8


        Hit, 1=,1=,8=, 2=, 1=, 8=, Then, hit “=” you will see X=0, hit “=” again, you will see Y=8.
        It means b=0 and c=8 !!!

        Therefore, the general formula is 2n2 + (0Xn) + 8
        or 2n2 + 8



        My son sec2 also do not know how to use the calculator , equation mode and this is only P5 question
        .

        1 Reply Last reply Reply Quote 0
        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          imacsg:
          Hi

          Thanks.

          I nearly fainted when I see, the teacher asked them to use

          this equation an2 + bn + c to solve above question:

          Using Fx 95Sg Plus calculator, set Mode 3 (Equation Mode), Then choose 1.
          The calculator will have 3 columns (a), (b) and (c). Arrange your 2 equations like this:

          (a) (b) (c)
          b + c = 8
          2b + c = 8


          Hit, 1=,1=,8=, 2=, 1=, 8=, Then, hit “=” you will see X=0, hit “=” again, you will see Y=8.
          It means b=0 and c=8 !!!

          Therefore, the general formula is 2n2 + (0Xn) + 8
          or 2n2 + 8



          My son sec2 also do not know how to use the calculator , equation mode and this is only P5 question
          .
          Hi
          I believe your child in the GEP.
          Yes, the \"correct way\" is to use the quadratic equation to find the nth term when the 2nd level difference is a constant, for eg if the question ask for the 100th number. But for this question, there is no need to work out the nth term because it is quite easy to find x.

          cheers.

          1 Reply Last reply Reply Quote 0
          • I Offline
            imacsg
            last edited by

            Hi MathIzzzFun,

            Thanks for your reply. My son is not in the GEP, but in the best class. I find if the child is not so strong in maths, if you teach them this method, they will not understand.

            Cheer.

            1 Reply Last reply Reply Quote 0
            • O Offline
              ongmt
              last edited by

              Jug X and Jug Y contain different amounts of water at first. 50% of water in Jug X was poured into Jug Y, Then 40% of water in Jug Y was poured into Jug X. The final amunt of water in Jug X to Jug Y was 7:6

              a) what wa the ratio of the amount of water in Jug X to Jug Y at first
              b) if there were 10 litres of water in Jug X at first, how much water was there in Jug X at the end.

              plse help:salute:

              1 Reply Last reply Reply Quote 0
              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                ongmt:
                Jug X and Jug Y contain different amounts of water at first. 50% of water in Jug X was poured into Jug Y, Then 40% of water in Jug Y was poured into Jug X. The final amunt of water in Jug X to Jug Y was 7:6

                a) what wa the ratio of the amount of water in Jug X to Jug Y at first
                b) if there were 10 litres of water in Jug X at first, how much water was there in Jug X at the end.

                plse help:salute:
                Hi
                a)
                in the end,
                X :Y --> 7u: 6u -- 6u represents 60% of Y after transfer of 40%.
                Before 2nd transfer, X:Y --> 7u - 4u : 6u + 4u = 3u : 10u
                -- 3u = 50% of X after transfer,
                at first,
                X: Y --> 6u: 7u

                b) X, at first : in the end --> 6u : 7u = 10 litres : 7/6 x 10 litres
                In the end, X --> 11 2/3 litres

                cheers.

                1 Reply Last reply Reply Quote 0
                • Y Offline
                  yapperz2000
                  last edited by

                  http://i50.tinypic.com/302t8ol.jpg\">

                  Hi!
                  I need help with this question.
                  Couldn't find the solution as it was catholic high prelims maths 2008
                  :udaman:

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    yapperz2000:
                    http://i50.tinypic.com/302t8ol.jpg\">

                    Hi!
                    I need help with this question.
                    Couldn't find the solution as it was catholic high prelims maths 2008
                    :udaman:
                    Hi
                    The units should be in square meters..

                    basically, you need to find two square numbers with a difference of 32 - listing the square numbers and using guess and check, for primary school students.

                    Square numbers : 1, 4, 9, 16, 25, 36, 49...
                    The two square numbers 4 & 36 gives a difference of 32 -
                    6x6 - 2x2 = 32

                    so, area of garden = 4m² -- a miniature garden !!!


                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • P Offline
                      petals73
                      last edited by

                      OMG. 2008 perlim? It came out in my girl P3 SA2 problem sum last yr!!! Can’t remember if she’s got it correct?

                      1 Reply Last reply Reply Quote 0
                      • sylphaS Offline
                        sylpha
                        last edited by

                        MathIzzzFun:
                        ppspbubble:

                        Rick sold a total of 90 chickens and ducks. He earned a total of $4 in every duck he sold and lost $2 on every chicken he sold. On the whole, he earned a total of $222. How many ducks and chickens did he sell?


                        Hi

                        number of chickens = [(90x4)-222]/6 = 23
                        number of ducks = 90 - 23 = 67

                        cheers.

                        Hi there
                        Btw, how would this be illustrated in the model method? I sort of understand the logic I cant graphically \"draw\" it. 🤷

                        1 Reply Last reply Reply Quote 0

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