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    Q&A - P3 Math

    Scheduled Pinned Locked Moved Primary 3
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    • S Offline
      SAHM Chew
      last edited by

      A teddy bear cost as much as 3 toy clowns. During a sale, both toys were sold for $12 less. For the new prices, a teddy bear cost as much as 6 toy clowns. How much did the teddy bear cost before the sale? Can anyone provide me with the model and workings? Thanks

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      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        SAHM Chew:
        A teddy bear cost as much as 3 toy clowns. During a sale, both toys were sold for $12 less. For the new prices, a teddy bear cost as much as 6 toy clowns. How much did the teddy bear cost before the sale? Can anyone provide me with the model and workings? Thanks

        Hi

        http://i44.tinypic.com/r85fdf.jpg\">

        cheers.

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        • S Offline
          SAHM Chew
          last edited by

          Ok, i know already. Thanks

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          • J Offline
            jwxh
            last edited by

            tks everyone!

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            • Y Offline
              Yerdua
              last edited by

              Hi hi,

              Need help with this qn:
              how many 4-digits numbers can you make using each of the following digits once: 2,2,5,9?

              Is there a formula to get the answer fast or do we have to list all number out as working?

              Thanks!

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              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                Yerdua:
                Hi hi,

                Need help with this qn:
                how many 4-digits numbers can you make using each of the following digits once: 2,2,5,9?

                Is there a formula to get the answer fast or do we have to list all number out as working?

                Thanks!
                Hi

                for p3, students are taught to list out the numbers.

                for maths olympiad students, they will be taught the \"shortcut\"
                number of 4 digit numbers = 4!/2!= 12
                4! = 1 x 2 x 3 x 4, 2! = 1 x 2

                Let the 4 digit number be ABCD, we can choose any of the 4 digits for A,
                then we will be left with only 3 digits to choose for B, and then 2 choices for C and finally 1 choice for D
                so, number of 4 digit numbers = 4 x 3 x 2 x 1 = 24
                but since there are two \"2\"s, there will be double counting of the \"2\"s. The \"2\"s can be arranged in 2 ways so we have to divide by 2 to get the final answer --> 24/2 = 12

                cheers.

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                • Y Offline
                  Yerdua
                  last edited by

                  Hi mathsizzzfun,


                  Thanks for ur prompt and clear reply!

                  Went to google for the answer and got even more blur cos of the two '2's. Thanks a lot! šŸ™‚

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                  • C Offline
                    chloecube
                    last edited by

                    Yerdua:
                    Hi mathsizzzfun,


                    Thanks for ur prompt and clear reply!

                    Went to google for the answer and got even more blur cos of the two '2's. Thanks a lot! šŸ™‚

                    :imcool: this is like buying 4D...

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                    • Y Offline
                      Yerdua
                      last edited by

                      Another qns :oops:


                      Ms Lee buys some sweets.
                      If she gives each pupil 5 sweets, she is left with 16 sweets.
                      If she gives each pupil 8 sweets, she is short of 5 sweets.
                      How many pupils does Miss Lee have?

                      Thanks!!

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                      • S Offline
                        Sun_2010
                        last edited by

                        Between case 1 and 2

                        the no of excess sweets each pupil gets = 8-5 = 3

                        This excess is provided by the 16 extra in case 1
                        and the 5 short in case 2 = 16+5= 21

                        therefore, No of pupil = 21 divided by 3 = 7

                        Hope my explanation is clear

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