Q&A - P3 Math
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hello comrades,
need your help to solve the following P4 Maths without using ALGEBRA. :?:
detailed explanation much needed. thanks.
Q35) May had 60 more apples than June. After June gave 1/3 of her apples away, May had twice as many apples as June.
How many apples did they both have at first ? -
Ogima:
It will be easier to see if you draw model. (I am not good at creating nice pictures, so let me try to explain the \"model\" I drew.)hello comrades,
need your help to solve the following P4 Maths without using ALGEBRA. :?:
detailed explanation much needed. thanks.
Q35) May had 60 more apples than June. After June gave 1/3 of her apples away, May had twice as many apples as June.
How many apples did they both have at first ?
May [----][----][----][----]
{indicate the last unit}<60>
June [----][----][////]
(the last unit for June is the given away part)
Each unit should be drawn same size.
From model, 1 unit = 60
May has 4 x 60 = 240
June has 3 x 60 = 180 initially -
Ogima:
hello comrades,
need your help to solve the following P4 Maths without using ALGEBRA. :?:
detailed explanation much needed. thanks.
Q35) May had 60 more apples than June. After June gave 1/3 of her apples away, May had twice as many apples as June.
How many apples did they both have at first ?
Let me try, please note it is not drawn in scale
a)assume June has 3 units, therefore May has 3 units +60
May has 3 unit + 60 more [ ][ ][ ][ 60 more ]
June has 3 unit [ ][ ][ ]
b) May gave away 1/3, that mean is 1 unit, hence the model became
May [ ][ ][ ][ 60 more ]
June [ ][ ]
May has twice as many apples as June, hence
[1 st Half ] [2nd half ]
------------- -----------------
May [ ][ ] [ ][ 60 more]
June [ ][ ]
c) Let look at the half of it
May [ ][ 60 more ]
June [ ][ ]
Canceal 1 unit, the other unit is equal to 60, therefore
June has 60+60+60+60 = 240
May has 60+60+60 = 180
Total = 240+180 = 420 apples
They have total of 420 apples
I hope the above is able to help you.
Cheer! -
//Moderator's note: Topics merged.
Can anyone help to solve this qn? tks.
Matthew and Paul have a sum of money at first. If Matthew gives Paul $80, he will have twice as much as Paul. If Matthew gives Paul $20, he will have thrice as much as Paul. How much money did Matthew have at first? -
Anxiousmom:
//Moderator's note: Topics merged.
Can anyone help to solve this qn? tks.
Matthew and Paul have a sum of money at first. If Matthew gives Paul $80, he will have twice as much as Paul. If Matthew gives Paul $20, he will have thrice as much as Paul. How much money did Matthew have at first?
Amended
[....][.....80.....][....][.....80......] = 2 big units
[....][.....80.....] = 1 big unit
[....][20][.60.][....][20][.60.][.60.] = 3 units
[....][20] = 1 unit
1u = 3 x 60 = 180
3u = 3 x 180 = 540
Matthew = 540 + 20 = $560 -
Anxiousmom:
Hi Anxiousmom,//Moderator's note: Topics merged.
Can anyone help to solve this qn? tks.
Matthew and Paul have a sum of money at first. If Matthew gives Paul $80, he will have twice as much as Paul. If Matthew gives Paul $20, he will have thrice as much as Paul. How much money did Matthew have at first?
I drew the models for both parts :
M [--------][--------][-80-]
P [-][-80-]
(note : [-][-80-] is same length as [-------])
M [------][------][------][20]
P [-][20]
(note : [-][20] same length as [-----], and the length for M for both models are the same)
Based on the models,
3(p+20) + 20 = 2 (p+80) + 80
p = 160
m = 2x(160+80) + 80 = 560
Matthew has $560 initially.
(but sorry, my soln seems a bit \"algebraic\", maybe someone can suggest a more \"modelic\" soln :lol: ) -
Hi Hi
Tks to Tang and elkniwt for your solutions. Hopefully my dau can absorb. -
Anxiousmom:
If Matthew gives Paul $80Hi Hi
Tks to Tang and elkniwt for your solutions. Hopefully my dau can absorb.
Amt of money at first :
Matthew : 2units + $80
Paul : 1unit - $80
If Matthew gives Paul $20
Amt of money at last :
Matthew : 2units + $80 - $20 = 3parts
Paul : (1units - $80) + $20 = 1parts
3parts = 2units +$60 (Matthew)
1part = 1unit - $60 (Paul)
3 parts = 3 units - $180
2units + $60 = 3units - $180
1units = $240
Amt of money Matthew had first = 2($240) + $80 = $560 -
Hi,
I have a math question need help?
\"Mrs Wong was short of $42 if she bought 5 similiar vases. So she bought 3 such vases and has $12 left. What was the cost of each vase?\"
Thankss.
Daddy :? -
Cost of each vase = $27
You need some other kind soul to show you how to solve via model mtd. I just itchy hand solving here :lol:
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