Q&A - P3 Math

[Anxiousmom]

//Moderator's note: Topics merged.


Can anyone help to solve this qn? tks.

Matthew and Paul have a sum of money at first. If Matthew gives Paul $80, he will have twice as much as Paul. If Matthew gives Paul $20, he will have thrice as much as Paul. How much money did Matthew have at first?

[Tang]

Anxiousmom:

//Moderator's note: Topics merged.


Can anyone help to solve this qn? tks.

Matthew and Paul have a sum of money at first. If Matthew gives Paul $80, he will have twice as much as Paul. If Matthew gives Paul $20, he will have thrice as much as Paul. How much money did Matthew have at first?

Amended

[....][.....80.....][....][.....80......] = 2 big units
[....][.....80.....] = 1 big unit


[....][20][.60.][....][20][.60.][.60.] = 3 units
[....][20] = 1 unit

1u = 3 x 60 = 180

3u = 3 x 180 = 540

Matthew = 540 + 20 = $560

[elkniwt]

Anxiousmom:

//Moderator's note: Topics merged.


Can anyone help to solve this qn? tks.

Matthew and Paul have a sum of money at first. If Matthew gives Paul $80, he will have twice as much as Paul. If Matthew gives Paul $20, he will have thrice as much as Paul. How much money did Matthew have at first?

Hi Anxiousmom,

I drew the models for both parts :

M [--------][--------][-80-]
P [-][-80-]

(note : [-][-80-] is same length as [-------])

M [------][------][------][20]
P [-][20]

(note : [-][20] same length as [-----], and the length for M for both models are the same)

Based on the models,

3(p+20) + 20 = 2 (p+80) + 80
p = 160
m = 2x(160+80) + 80 = 560

Matthew has $560 initially.

(but sorry, my soln seems a bit \"algebraic\", maybe someone can suggest a more \"modelic\" soln :lol: )

[Anxiousmom]

Hi Hi

Tks to Tang and elkniwt for your solutions. Hopefully my dau can absorb.

[Dharma]

Anxiousmom:

Hi Hi

Tks to Tang and elkniwt for your solutions. Hopefully my dau can absorb.

If Matthew gives Paul $80

Amt of money at first :
Matthew : 2units + $80
Paul : 1unit - $80

If Matthew gives Paul $20

Amt of money at last :
Matthew : 2units + $80 - $20 = 3parts
Paul : (1units - $80) + $20 = 1parts

3parts = 2units +$60 (Matthew)
1part = 1unit - $60 (Paul)
3 parts = 3 units - $180

2units + $60 = 3units - $180
1units = $240

Amt of money Matthew had first = 2($240) + $80 = $560

[Daddy]

Hi,


I have a math question need help?

\"Mrs Wong was short of $42 if she bought 5 similiar vases. So she bought 3 such vases and has $12 left. What was the cost of each vase?\"

Thankss.
Daddy :?

[radiantmum]

Cost of each vase = $27


You need some other kind soul to show you how to solve via model mtd. I just itchy hand solving here :lol:

[CeciliaHua]

Daddy:

Hi,


I have a math question need help?

\"Mrs Wong was short of $42 if she bought 5 similiar vases. So she bought 3 such vases and has $12 left. What was the cost of each vase?\"

Thankss.
Daddy :?

If buying 3 vases still have $12 left, then buying additional 2 more vases will need $12+$42=$54. That means each vase cost $27.

[Daddy]

HI,


Any model? Not so understand…

[CeciliaHua]

Daddy:

HI,


Any model? Not so understand...

I'm not sure if this is correct.

Five boxes represent the 5 vases
[][][][][]

since you need additional $42 to buy all 5 vases, the next model is 3 boxes and the other 2 boxes should be $12+$42. Why $12? Because when you buy 3 vases, you have $12 left.

[][][]$12+$42

Hope this helps.